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26n^2+n-6=0
a = 26; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·26·(-6)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-25}{2*26}=\frac{-26}{52} =-1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+25}{2*26}=\frac{24}{52} =6/13 $
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